110002131400433 has 2 divisors, whose sum is σ = 110002131400434. Its totient is φ = 110002131400432.

The previous prime is 110002131400417. The next prime is 110002131400453. The reversal of 110002131400433 is 334004131200011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96745774699249 + 13256356701184 = 9835943^2 + 3640928^2 .

It is a cyclic number.

It is not a de Polignac number, because 110002131400433 - 2⁴ = 110002131400417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110002131400399 and 110002131400408.

It is not a weakly prime, because it can be changed into another prime (110002131400453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001065700216 + 55001065700217.

It is an arithmetic number, because the mean of its divisors is an integer number (55001065700217).

Almost surely, 2^{110002131400433} is an apocalyptic number.

It is an amenable number.

110002131400433 is a deficient number, since it is larger than the sum of its proper divisors (1).

110002131400433 is an equidigital number, since it uses as much as digits as its factorization.

110002131400433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 110002131400433 its reverse (334004131200011), we get a palindrome (444006262600444).

The spelling of 110002131400433 in words is "one hundred ten trillion, two billion, one hundred thirty-one million, four hundred thousand, four hundred thirty-three".