Base | Representation |
---|---|
bin | 110011001110010100… |
… | …0110101100101010010 |
3 | 101111221020102100202022 |
4 | 1212130220311211102 |
5 | 3300241021231310 |
6 | 122311223251442 |
7 | 10642645464035 |
oct | 1463450654522 |
9 | 344836370668 |
10 | 110002133330 |
11 | 427193779a1 |
12 | 1939b5a9b82 |
13 | a4b0a95c2b |
14 | 54775bb01c |
15 | 2cdc3b9a55 |
hex | 199ca35952 |
110002133330 has 32 divisors (see below), whose sum is σ = 198344360448. Its totient is φ = 43925252800.
The previous prime is 110002133323. The next prime is 110002133413. The reversal of 110002133330 is 33331200011.
110002133330 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-4 number, since 4×1100021333304 (a number of 45 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 110002133299 and 110002133308.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18388940 + ... + 18394920.
It is an arithmetic number, because the mean of its divisors is an integer number (6198261264).
Almost surely, 2110002133330 is an apocalyptic number.
110002133330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
110002133330 is a deficient number, since it is larger than the sum of its proper divisors (88342227118).
110002133330 is a wasteful number, since it uses less digits than its factorization.
110002133330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8842.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 110002133330 its reverse (33331200011), we get a palindrome (143333333341).
The spelling of 110002133330 in words is "one hundred ten billion, two million, one hundred thirty-three thousand, three hundred thirty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •