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11000219981 is a prime number
BaseRepresentation
bin10100011111010101…
…00000100101001101
31001101121212001222212
422033222200211031
5140012024014411
65015312520205
7536411220122
oct121752404515
931347761885
1011000219981
1147353790a3
12216bb50065
131063ca380a
14764d2a749
15445ad468b
hex28faa094d

11000219981 has 2 divisors, whose sum is σ = 11000219982. Its totient is φ = 11000219980.

The previous prime is 11000219939. The next prime is 11000220019. The reversal of 11000219981 is 18991200011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10378515625 + 621704356 = 101875^2 + 24934^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000219981 - 226 = 10933111117 is a prime.

It is a super-2 number, since 2×110002199812 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000219921) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500109990 + 5500109991.

It is an arithmetic number, because the mean of its divisors is an integer number (5500109991).

Almost surely, 211000219981 is an apocalyptic number.

It is an amenable number.

11000219981 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000219981 is an equidigital number, since it uses as much as digits as its factorization.

11000219981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 32.

Adding to 11000219981 its reverse (18991200011), we get a palindrome (29991419992).

The spelling of 11000219981 in words is "eleven billion, two hundred nineteen thousand, nine hundred eighty-one".