Base | Representation |
---|---|
bin | 10100011111010101… |
… | …00000100101001101 |
3 | 1001101121212001222212 |
4 | 22033222200211031 |
5 | 140012024014411 |
6 | 5015312520205 |
7 | 536411220122 |
oct | 121752404515 |
9 | 31347761885 |
10 | 11000219981 |
11 | 47353790a3 |
12 | 216bb50065 |
13 | 1063ca380a |
14 | 764d2a749 |
15 | 445ad468b |
hex | 28faa094d |
11000219981 has 2 divisors, whose sum is σ = 11000219982. Its totient is φ = 11000219980.
The previous prime is 11000219939. The next prime is 11000220019. The reversal of 11000219981 is 18991200011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10378515625 + 621704356 = 101875^2 + 24934^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000219981 - 226 = 10933111117 is a prime.
It is a super-2 number, since 2×110002199812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000219921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500109990 + 5500109991.
It is an arithmetic number, because the mean of its divisors is an integer number (5500109991).
Almost surely, 211000219981 is an apocalyptic number.
It is an amenable number.
11000219981 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000219981 is an equidigital number, since it uses as much as digits as its factorization.
11000219981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 32.
Adding to 11000219981 its reverse (18991200011), we get a palindrome (29991419992).
The spelling of 11000219981 in words is "eleven billion, two hundred nineteen thousand, nine hundred eighty-one".
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