11000220113 has 2 divisors, whose sum is σ = 11000220114. Its totient is φ = 11000220112.

The previous prime is 11000220109. The next prime is 11000220163. The reversal of 11000220113 is 31102200011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7990929664 + 3009290449 = 89392^2 + 54857^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000220113 - 2² = 11000220109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11000220094 and 11000220103.

It is not a weakly prime, because it can be changed into another prime (11000220163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500110056 + 5500110057.

It is an arithmetic number, because the mean of its divisors is an integer number (5500110057).

Almost surely, 2^11000220113 is an apocalyptic number.

It is an amenable number.

11000220113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000220113 is an equidigital number, since it uses as much as digits as its factorization.

11000220113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 11000220113 its reverse (31102200011), we get a palindrome (42102420124).

The spelling of 11000220113 in words is "eleven billion, two hundred twenty thousand, one hundred thirteen".