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11000220212022 = 231833370035337
BaseRepresentation
bin1010000000010011000000…
…1101111101101100110110
31102221121111021000121102020
42200010300031331230312
52420211422333241042
635221233103254010
72213511466022016
oct240046015755466
942847437017366
1011000220212022
113561192597518
121297abb5aa306
1361a415c37122
142a05b08d9c46
1514121aba73ec
hexa013037db36

11000220212022 has 8 divisors (see below), whose sum is σ = 22000440424056. Its totient is φ = 3666740070672.

The previous prime is 11000220211999. The next prime is 11000220212039. The reversal of 11000220212022 is 22021202200011.

It is a sphenic number, since it is the product of 3 distinct primes.

11000220212022 is an admirable number.

It is a junction number, because it is equal to n+sod(n) for n = 11000220211992 and 11000220212010.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 916685017663 + ... + 916685017674.

It is an arithmetic number, because the mean of its divisors is an integer number (2750055053007).

Almost surely, 211000220212022 is an apocalyptic number.

11000220212022 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11000220212022 is a wasteful number, since it uses less digits than its factorization.

11000220212022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1833370035342.

The product of its (nonzero) digits is 64, while the sum is 15.

Adding to 11000220212022 its reverse (22021202200011), we get a palindrome (33021422412033).

The spelling of 11000220212022 in words is "eleven trillion, two hundred twenty million, two hundred twelve thousand, twenty-two".

Divisors: 1 2 3 6 1833370035337 3666740070674 5500110106011 11000220212022