Base | Representation |
---|---|
bin | 10000000000011110011… |
… | …011101110011000010000 |
3 | 10220011100102212021000120 |
4 | 100000132123232120100 |
5 | 121010321141241422 |
6 | 2201202045350240 |
7 | 142321401345615 |
oct | 20003633563020 |
9 | 3804312767016 |
10 | 1100022212112 |
11 | 39457595230a |
12 | 159237268380 |
13 | 7c968584535 |
14 | 3b35440a50c |
15 | 1d9328dc45c |
hex | 1001e6ee610 |
1100022212112 has 80 divisors (see below), whose sum is σ = 2895009374208. Its totient is φ = 359857065600.
The previous prime is 1100022212083. The next prime is 1100022212141. The reversal of 1100022212112 is 2112122200011.
It is an interprime number because it is at equal distance from previous prime (1100022212083) and next prime (1100022212141).
It is a junction number, because it is equal to n+sod(n) for n = 1100022212091 and 1100022212100.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 312688 + ... + 1515855.
Almost surely, 21100022212112 is an apocalyptic number.
1100022212112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1100022212112 is an abundant number, since it is smaller than the sum of its proper divisors (1794987162096).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1100022212112 is a wasteful number, since it uses less digits than its factorization.
1100022212112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1828788 (or 1828782 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 1100022212112 its reverse (2112122200011), we get a palindrome (3212144412123).
The spelling of 1100022212112 in words is "one trillion, one hundred billion, twenty-two million, two hundred twelve thousand, one hundred twelve".
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