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11000232550493 is a prime number
BaseRepresentation
bin1010000000010011000011…
…1101000010000001011101
31102221121112010020110121122
42200010300331002001131
52420211434013103433
635221234223540325
72213512005631154
oct240046075020135
942847463213548
1011000232550493
1135611995545aa
121297b0375a6a5
1361a4186671b4
142a05b23cc59b
1514121bce3198
hexa0130f4205d

11000232550493 has 2 divisors, whose sum is σ = 11000232550494. Its totient is φ = 11000232550492.

The previous prime is 11000232550487. The next prime is 11000232550561. The reversal of 11000232550493 is 39405523200011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8405111310649 + 2595121239844 = 2899157^2 + 1610938^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000232550493 - 224 = 11000215773277 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000232555493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500116275246 + 5500116275247.

It is an arithmetic number, because the mean of its divisors is an integer number (5500116275247).

Almost surely, 211000232550493 is an apocalyptic number.

It is an amenable number.

11000232550493 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000232550493 is an equidigital number, since it uses as much as digits as its factorization.

11000232550493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32400, while the sum is 35.

The spelling of 11000232550493 in words is "eleven trillion, two hundred thirty-two million, five hundred fifty thousand, four hundred ninety-three".