Base | Representation |
---|---|
bin | 10100011111010101… |
… | …00011110000101011 |
3 | 1001101121212201212011 |
4 | 22033222203300223 |
5 | 140012024424003 |
6 | 5015313100351 |
7 | 536411303104 |
oct | 121752436053 |
9 | 31347781764 |
10 | 11000233003 |
11 | 4735387961 |
12 | 216bb576b7 |
13 | 1063ca9716 |
14 | 764d313ab |
15 | 445ad846d |
hex | 28faa3c2b |
11000233003 has 4 divisors (see below), whose sum is σ = 11042059248. Its totient is φ = 10958406760.
The previous prime is 11000232967. The next prime is 11000233007. The reversal of 11000233003 is 30033200011.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30033200011 = 46103 ⋅651437.
It is a cyclic number.
It is not a de Polignac number, because 11000233003 - 29 = 11000232491 is a prime.
It is a super-2 number, since 2×110002330032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11000233007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20912728 + ... + 20913253.
It is an arithmetic number, because the mean of its divisors is an integer number (2760514812).
Almost surely, 211000233003 is an apocalyptic number.
11000233003 is a deficient number, since it is larger than the sum of its proper divisors (41826245).
11000233003 is an equidigital number, since it uses as much as digits as its factorization.
11000233003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41826244.
The product of its (nonzero) digits is 54, while the sum is 13.
Adding to 11000233003 its reverse (30033200011), we get a palindrome (41033433014).
The spelling of 11000233003 in words is "eleven billion, two hundred thirty-three thousand, three".
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