1100023311133 has 4 divisors (see below), whose sum is σ = 1100030008000. Its totient is φ = 1100016614268.

The previous prime is 1100023311131. The next prime is 1100023311181. The reversal of 1100023311133 is 3311133200011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1100023311133 - 2¹ = 1100023311131 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1100023311133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100023311131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3095685 + ... + 3432682.

It is an arithmetic number, because the mean of its divisors is an integer number (275007502000).

Almost surely, 2^{1100023311133} is an apocalyptic number.

It is an amenable number.

1100023311133 is a deficient number, since it is larger than the sum of its proper divisors (6696867).

1100023311133 is an equidigital number, since it uses as much as digits as its factorization.

1100023311133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6696866.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1100023311133 its reverse (3311133200011), we get a palindrome (4411156511144).

The spelling of 1100023311133 in words is "one trillion, one hundred billion, twenty-three million, three hundred eleven thousand, one hundred thirty-three".