Base | Representation |
---|---|
bin | 1010000000010011000011… |
… | …1111100011000010110001 |
3 | 1102221121112011110222100001 |
4 | 2200010300333203002301 |
5 | 2420211434200210113 |
6 | 35221234250030001 |
7 | 2213512014346054 |
oct | 240046077430261 |
9 | 42847464428301 |
10 | 11000233210033 |
11 | 3561199965081 |
12 | 1297b03a18301 |
13 | 61a418838462 |
14 | 2a05b2520a9b |
15 | 14121bdc37dd |
hex | a0130fe30b1 |
11000233210033 has 2 divisors, whose sum is σ = 11000233210034. Its totient is φ = 11000233210032.
The previous prime is 11000233209991. The next prime is 11000233210049. The reversal of 11000233210033 is 33001233200011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5688830806129 + 5311402403904 = 2385127^2 + 2304648^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000233210033 - 221 = 11000231112881 is a prime.
It is a super-2 number, since 2×110002332100332 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11000233210063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500116605016 + 5500116605017.
It is an arithmetic number, because the mean of its divisors is an integer number (5500116605017).
Almost surely, 211000233210033 is an apocalyptic number.
It is an amenable number.
11000233210033 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000233210033 is an equidigital number, since it uses as much as digits as its factorization.
11000233210033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 11000233210033 its reverse (33001233200011), we get a palindrome (44001466410044).
The spelling of 11000233210033 in words is "eleven trillion, two hundred thirty-three million, two hundred ten thousand, thirty-three".
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