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11000241400132 = 222750060350033
BaseRepresentation
bin1010000000010011000101…
…1110110010100101000100
31102221121112201220002001001
42200010301132302211010
52420211443244301012
635221235141343044
72213512144066645
oct240046136624504
942847481802031
1011000241400132
1135611a3549456
121297b06707a84
1361a41a44527a
142a05b36536cc
1514121c990357
hexa01317b2944

11000241400132 has 6 divisors (see below), whose sum is σ = 19250422450238. Its totient is φ = 5500120700064.

The previous prime is 11000241400103. The next prime is 11000241400147. The reversal of 11000241400132 is 23100414200011.

It can be written as a sum of positive squares in only one way, i.e., 10153756758016 + 846484642116 = 3186496^2 + 920046^2 .

It is a super-2 number, since 2×110002414001322 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1375030175013 + ... + 1375030175020.

Almost surely, 211000241400132 is an apocalyptic number.

It is an amenable number.

11000241400132 is a deficient number, since it is larger than the sum of its proper divisors (8250181050106).

11000241400132 is a wasteful number, since it uses less digits than its factorization.

11000241400132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2750060350037 (or 2750060350035 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 11000241400132 its reverse (23100414200011), we get a palindrome (34100655600143).

The spelling of 11000241400132 in words is "eleven trillion, two hundred forty-one million, four hundred thousand, one hundred thirty-two".

Divisors: 1 2 4 2750060350033 5500120700066 11000241400132