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1100030020033 = 71429109970011
BaseRepresentation
bin10000000000011110111…
…001100000100111000001
310220011100222112221110211
4100000132321200213001
5121010330141120113
62201202524554121
7142321524615340
oct20003671404701
93804328487424
101100030020033
1139457a2a553a
121592399b2941
137c96a0893c9
143b35547db57
151d933430b3d
hex1001ee609c1

1100030020033 has 8 divisors (see below), whose sum is σ = 1258056937280. Its totient is φ = 942223045680.

The previous prime is 1100030020031. The next prime is 1100030020039. The reversal of 1100030020033 is 3300200300011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1100030020033 - 21 = 1100030020031 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1100030019995 and 1100030020022.

It is not an unprimeable number, because it can be changed into a prime (1100030020031) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 54975003 + ... + 54995008.

It is an arithmetic number, because the mean of its divisors is an integer number (157257117160).

Almost surely, 21100030020033 is an apocalyptic number.

It is an amenable number.

1100030020033 is a deficient number, since it is larger than the sum of its proper divisors (158026917247).

1100030020033 is a wasteful number, since it uses less digits than its factorization.

1100030020033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 109971447.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 1100030020033 its reverse (3300200300011), we get a palindrome (4400230320044).

The spelling of 1100030020033 in words is "one trillion, one hundred billion, thirty million, twenty thousand, thirty-three".

Divisors: 1 7 1429 10003 109970011 769790077 157147145719 1100030020033