Base | Representation |
---|---|
bin | 1010000000010011010110… |
… | …0100011111000111010011 |
3 | 1102221121201111222102021211 |
4 | 2200010311210133013103 |
5 | 2420212113330032011 |
6 | 35221250032000551 |
7 | 2213513636151532 |
oct | 240046544370723 |
9 | 42847644872254 |
10 | 11000310002131 |
11 | 356122924511a |
12 | 1297b25690157 |
13 | 61a42b714678 |
14 | 2a05bc7d0319 |
15 | 1412239e1b21 |
hex | a013591f1d3 |
11000310002131 has 2 divisors, whose sum is σ = 11000310002132. Its totient is φ = 11000310002130.
The previous prime is 11000310002111. The next prime is 11000310002197. The reversal of 11000310002131 is 13120001300011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11000310002131 - 29 = 11000310001619 is a prime.
It is a super-3 number, since 3×110003100021313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (11000310002111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500155001065 + 5500155001066.
It is an arithmetic number, because the mean of its divisors is an integer number (5500155001066).
Almost surely, 211000310002131 is an apocalyptic number.
11000310002131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000310002131 is an equidigital number, since it uses as much as digits as its factorization.
11000310002131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 11000310002131 its reverse (13120001300011), we get a palindrome (24120311302142).
The spelling of 11000310002131 in words is "eleven trillion, three hundred ten million, two thousand, one hundred thirty-one".
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