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11000310002131 is a prime number
BaseRepresentation
bin1010000000010011010110…
…0100011111000111010011
31102221121201111222102021211
42200010311210133013103
52420212113330032011
635221250032000551
72213513636151532
oct240046544370723
942847644872254
1011000310002131
11356122924511a
121297b25690157
1361a42b714678
142a05bc7d0319
151412239e1b21
hexa013591f1d3

11000310002131 has 2 divisors, whose sum is σ = 11000310002132. Its totient is φ = 11000310002130.

The previous prime is 11000310002111. The next prime is 11000310002197. The reversal of 11000310002131 is 13120001300011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11000310002131 - 29 = 11000310001619 is a prime.

It is a super-3 number, since 3×110003100021313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (11000310002111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500155001065 + 5500155001066.

It is an arithmetic number, because the mean of its divisors is an integer number (5500155001066).

Almost surely, 211000310002131 is an apocalyptic number.

11000310002131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000310002131 is an equidigital number, since it uses as much as digits as its factorization.

11000310002131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11000310002131 its reverse (13120001300011), we get a palindrome (24120311302142).

The spelling of 11000310002131 in words is "eleven trillion, three hundred ten million, two thousand, one hundred thirty-one".