110003102002121 has 2 divisors, whose sum is σ = 110003102002122. Its totient is φ = 110003102002120.

The previous prime is 110003102002109. The next prime is 110003102002133. The reversal of 110003102002121 is 121200201300011.

It is a balanced prime because it is at equal distance from previous prime (110003102002109) and next prime (110003102002133).

It can be written as a sum of positive squares in only one way, i.e., 75645462553600 + 34357639448521 = 8697440^2 + 5861539^2 .

It is a cyclic number.

It is not a de Polignac number, because 110003102002121 - 2¹⁰ = 110003102001097 is a prime.

It is a super-3 number, since 3×110003102002121³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110003102002096 and 110003102002105.

It is not a weakly prime, because it can be changed into another prime (110003102002021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001551001060 + 55001551001061.

It is an arithmetic number, because the mean of its divisors is an integer number (55001551001061).

Almost surely, 2^{110003102002121} is an apocalyptic number.

It is an amenable number.

110003102002121 is a deficient number, since it is larger than the sum of its proper divisors (1).

110003102002121 is an equidigital number, since it uses as much as digits as its factorization.

110003102002121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 110003102002121 its reverse (121200201300011), we get a palindrome (231203303302132).

The spelling of 110003102002121 in words is "one hundred ten trillion, three billion, one hundred two million, two thousand, one hundred twenty-one".