Base | Representation |
---|---|
bin | 10100011111010101… |
… | …10111000100111010 |
3 | 1001101122000202101111 |
4 | 22033222313010322 |
5 | 140012034441442 |
6 | 5015314510534 |
7 | 536412052552 |
oct | 121752670472 |
9 | 31348022344 |
10 | 11000312122 |
11 | 4735431348 |
12 | 216bb9544a |
13 | 1064006737 |
14 | 764d52162 |
15 | 445b01b17 |
hex | 28fab713a |
11000312122 has 4 divisors (see below), whose sum is σ = 16500468186. Its totient is φ = 5500156060.
The previous prime is 11000312117. The next prime is 11000312129. The reversal of 11000312122 is 22121300011.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10057883521 + 942428601 = 100289^2 + 30699^2 .
It is a super-3 number, since 3×110003121223 (a number of 31 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (11000312129) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750078029 + ... + 2750078032.
Almost surely, 211000312122 is an apocalyptic number.
11000312122 is a deficient number, since it is larger than the sum of its proper divisors (5500156064).
11000312122 is an equidigital number, since it uses as much as digits as its factorization.
11000312122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5500156063.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 11000312122 its reverse (22121300011), we get a palindrome (33121612133).
The spelling of 11000312122 in words is "eleven billion, three hundred twelve thousand, one hundred twenty-two".
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