11000313223 has 4 divisors (see below), whose sum is σ = 11032955440. Its totient is φ = 10967671008.

The previous prime is 11000313197. The next prime is 11000313251. The reversal of 11000313223 is 32231300011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32231300011 = 18353 ⋅1756187.

It is a cyclic number.

It is not a de Polignac number, because 11000313223 - 2⁹ = 11000312711 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11000313197 and 11000313206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11000313923) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16320603 + ... + 16321276.

It is an arithmetic number, because the mean of its divisors is an integer number (2758238860).

Almost surely, 2^11000313223 is an apocalyptic number.

11000313223 is a deficient number, since it is larger than the sum of its proper divisors (32642217).

11000313223 is an equidigital number, since it uses as much as digits as its factorization.

11000313223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32642216.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 11000313223 its reverse (32231300011), we get a palindrome (43231613234).

The spelling of 11000313223 in words is "eleven billion, three hundred thirteen thousand, two hundred twenty-three".