Base | Representation |
---|---|
bin | 10100011111010101… |
… | …10111010111100111 |
3 | 1001101122000211000211 |
4 | 22033222313113213 |
5 | 140012040011234 |
6 | 5015314520251 |
7 | 536412056212 |
oct | 121752672747 |
9 | 31348024024 |
10 | 11000313319 |
11 | 4735432236 |
12 | 216bb96087 |
13 | 1064007148 |
14 | 764d52779 |
15 | 445b02164 |
hex | 28fab75e7 |
11000313319 has 2 divisors, whose sum is σ = 11000313320. Its totient is φ = 11000313318.
The previous prime is 11000313299. The next prime is 11000313349. The reversal of 11000313319 is 91331300011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11000313319 - 217 = 11000182247 is a prime.
It is a super-2 number, since 2×110003133192 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11000313319.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000313349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500156659 + 5500156660.
It is an arithmetic number, because the mean of its divisors is an integer number (5500156660).
Almost surely, 211000313319 is an apocalyptic number.
11000313319 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000313319 is an equidigital number, since it uses as much as digits as its factorization.
11000313319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 22.
The spelling of 11000313319 in words is "eleven billion, three hundred thirteen thousand, three hundred nineteen".
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