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11000330313131 is a prime number
BaseRepresentation
bin1010000000010011011011…
…0001111101110110101011
31102221121202221012022202002
42200010312301331312223
52420212134030010011
635221252035201215
72213514303614345
oct240046661756653
942847687168662
1011000330313131
113561239758075
121297b3044620b
1361a4329a6503
142a05c139a295
151412256a4c3b
hexa0136c7ddab

11000330313131 has 2 divisors, whose sum is σ = 11000330313132. Its totient is φ = 11000330313130.

The previous prime is 11000330313103. The next prime is 11000330313143. The reversal of 11000330313131 is 13131303300011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11000330313131 - 238 = 10725452406187 is a prime.

It is a super-2 number, since 2×110003303131312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11000330313151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500165156565 + 5500165156566.

It is an arithmetic number, because the mean of its divisors is an integer number (5500165156566).

Almost surely, 211000330313131 is an apocalyptic number.

11000330313131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000330313131 is an equidigital number, since it uses as much as digits as its factorization.

11000330313131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 11000330313131 its reverse (13131303300011), we get a palindrome (24131633613142).

The spelling of 11000330313131 in words is "eleven trillion, three hundred thirty million, three hundred thirteen thousand, one hundred thirty-one".