11000332213141 has 2 divisors, whose sum is σ = 11000332213142. Its totient is φ = 11000332213140.

The previous prime is 11000332213111. The next prime is 11000332213153. The reversal of 11000332213141 is 14131223300011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10953922128241 + 46410084900 = 3309671^2 + 215430^2 .

It is an emirp because it is prime and its reverse (14131223300011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11000332213141 - 2¹¹ = 11000332211093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000332213111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500166106570 + 5500166106571.

It is an arithmetic number, because the mean of its divisors is an integer number (5500166106571).

Almost surely, 2^{11000332213141} is an apocalyptic number.

It is an amenable number.

11000332213141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000332213141 is an equidigital number, since it uses as much as digits as its factorization.

11000332213141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 11000332213141 its reverse (14131223300011), we get a palindrome (25131555513152).

The spelling of 11000332213141 in words is "eleven trillion, three hundred thirty-two million, two hundred thirteen thousand, one hundred forty-one".