Base | Representation |
---|---|
bin | 10100011111010101… |
… | …11100001101001011 |
3 | 1001101122001211012121 |
4 | 22033222330031023 |
5 | 140012041130011 |
6 | 5015315152111 |
7 | 536412201034 |
oct | 121752741513 |
9 | 31348054177 |
10 | 11000333131 |
11 | 4735446107 |
12 | 216bba5637 |
13 | 1064013178 |
14 | 764d59a8b |
15 | 445b07e71 |
hex | 28fabc34b |
11000333131 has 2 divisors, whose sum is σ = 11000333132. Its totient is φ = 11000333130.
The previous prime is 11000333129. The next prime is 11000333173. The reversal of 11000333131 is 13133300011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11000333131 - 21 = 11000333129 is a prime.
It is a super-2 number, since 2×110003331312 (a number of 21 digits) contains 22 as substring.
Together with 11000333129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11000333231) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500166565 + 5500166566.
It is an arithmetic number, because the mean of its divisors is an integer number (5500166566).
Almost surely, 211000333131 is an apocalyptic number.
11000333131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000333131 is an equidigital number, since it uses as much as digits as its factorization.
11000333131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 11000333131 its reverse (13133300011), we get a palindrome (24133633142).
The spelling of 11000333131 in words is "eleven billion, three hundred thirty-three thousand, one hundred thirty-one".
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