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11000333313012 = 2238919752283947
BaseRepresentation
bin1010000000010011011011…
…1101011010001111110100
31102221121210010211201210210
42200010312331122033310
52420212140312004022
635221252223345420
72213514341250351
oct240046675321764
942847703751723
1011000333313012
113561240416a0a
121297b31452270
1361a4334b6aa4
142a05c193b628
15141225a98a0c
hexa0136f5a3f4

11000333313012 has 48 divisors (see below), whose sum is σ = 26087598694080. Its totient is φ = 3607174002432.

The previous prime is 11000333313007. The next prime is 11000333313017. The reversal of 11000333313012 is 21031333300011.

11000333313012 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (11000333313007) and next prime (11000333313017).

It is a self number, because there is not a number n which added to its sum of digits gives 11000333313012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11000333313017) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25931578 + ... + 26352369.

It is an arithmetic number, because the mean of its divisors is an integer number (543491639460).

Almost surely, 211000333313012 is an apocalyptic number.

11000333313012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

11000333313012 is an abundant number, since it is smaller than the sum of its proper divisors (15087265381068).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11000333313012 is a wasteful number, since it uses less digits than its factorization.

11000333313012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 52284240 (or 52284238 counting only the distinct ones).

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 11000333313012 its reverse (21031333300011), we get a palindrome (32031666613023).

The spelling of 11000333313012 in words is "eleven trillion, three hundred thirty-three million, three hundred thirteen thousand, twelve".

Divisors: 1 2 3 4 6 12 89 178 197 267 356 394 534 591 788 1068 1182 2364 17533 35066 52599 70132 105198 210396 52283947 104567894 156851841 209135788 313703682 627407364 4653271283 9306542566 10299937559 13959813849 18613085132 20599875118 27919627698 30899812677 41199750236 55839255396 61799625354 123599250708 916694442751 1833388885502 2750083328253 3666777771004 5500166656506 11000333313012