Base | Representation |
---|---|
bin | 1010000000010011011110… |
… | …1010100011111100010001 |
3 | 1102221121210222010002000011 |
4 | 2200010313222203330101 |
5 | 2420212201324233301 |
6 | 35221253325154521 |
7 | 2213514543665242 |
oct | 240046752437421 |
9 | 42847728102004 |
10 | 11000345149201 |
11 | 3561247070691 |
12 | 1297b353bba41 |
13 | 61a435a9c355 |
14 | 2a05c333ccc9 |
15 | 141226b35a51 |
hex | a0137aa3f11 |
11000345149201 has 2 divisors, whose sum is σ = 11000345149202. Its totient is φ = 11000345149200.
The previous prime is 11000345149139. The next prime is 11000345149217. The reversal of 11000345149201 is 10294154300011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9510907968576 + 1489437180625 = 3083976^2 + 1220425^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000345149201 - 223 = 11000336760593 is a prime.
It is not a weakly prime, because it can be changed into another prime (11000345149231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500172574600 + 5500172574601.
It is an arithmetic number, because the mean of its divisors is an integer number (5500172574601).
Almost surely, 211000345149201 is an apocalyptic number.
It is an amenable number.
11000345149201 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000345149201 is an equidigital number, since it uses as much as digits as its factorization.
11000345149201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 31.
Adding to 11000345149201 its reverse (10294154300011), we get a palindrome (21294499449212).
The spelling of 11000345149201 in words is "eleven trillion, three hundred forty-five million, one hundred forty-nine thousand, two hundred one".
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