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11000345149217 is a prime number
BaseRepresentation
bin1010000000010011011110…
…1010100011111100100001
31102221121210222010002000202
42200010313222203330201
52420212201324233332
635221253325154545
72213514543665264
oct240046752437441
942847728102022
1011000345149217
1135612470706a6
121297b353bba55
1361a435a9c368
142a05c333ccdb
15141226b35a62
hexa0137aa3f21

11000345149217 has 2 divisors, whose sum is σ = 11000345149218. Its totient is φ = 11000345149216.

The previous prime is 11000345149201. The next prime is 11000345149229. The reversal of 11000345149217 is 71294154300011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10993674180241 + 6670968976 = 3315671^2 + 81676^2 .

It is an emirp because it is prime and its reverse (71294154300011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11000345149217 - 24 = 11000345149201 is a prime.

It is not a weakly prime, because it can be changed into another prime (11000345149237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500172574608 + 5500172574609.

It is an arithmetic number, because the mean of its divisors is an integer number (5500172574609).

Almost surely, 211000345149217 is an apocalyptic number.

It is an amenable number.

11000345149217 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000345149217 is an equidigital number, since it uses as much as digits as its factorization.

11000345149217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30240, while the sum is 38.

Adding to 11000345149217 its reverse (71294154300011), we get a palindrome (82294499449228).

The spelling of 11000345149217 in words is "eleven trillion, three hundred forty-five million, one hundred forty-nine thousand, two hundred seventeen".