Base | Representation |
---|---|
bin | 1010000000010011011110… |
… | …1010100011111100100001 |
3 | 1102221121210222010002000202 |
4 | 2200010313222203330201 |
5 | 2420212201324233332 |
6 | 35221253325154545 |
7 | 2213514543665264 |
oct | 240046752437441 |
9 | 42847728102022 |
10 | 11000345149217 |
11 | 35612470706a6 |
12 | 1297b353bba55 |
13 | 61a435a9c368 |
14 | 2a05c333ccdb |
15 | 141226b35a62 |
hex | a0137aa3f21 |
11000345149217 has 2 divisors, whose sum is σ = 11000345149218. Its totient is φ = 11000345149216.
The previous prime is 11000345149201. The next prime is 11000345149229. The reversal of 11000345149217 is 71294154300011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10993674180241 + 6670968976 = 3315671^2 + 81676^2 .
It is an emirp because it is prime and its reverse (71294154300011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11000345149217 - 24 = 11000345149201 is a prime.
It is not a weakly prime, because it can be changed into another prime (11000345149237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500172574608 + 5500172574609.
It is an arithmetic number, because the mean of its divisors is an integer number (5500172574609).
Almost surely, 211000345149217 is an apocalyptic number.
It is an amenable number.
11000345149217 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000345149217 is an equidigital number, since it uses as much as digits as its factorization.
11000345149217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30240, while the sum is 38.
Adding to 11000345149217 its reverse (71294154300011), we get a palindrome (82294499449228).
The spelling of 11000345149217 in words is "eleven trillion, three hundred forty-five million, one hundred forty-nine thousand, two hundred seventeen".
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