11000401314 has 96 divisors (see below), whose sum is σ = 26847054720. Its totient is φ = 2990389248.

The previous prime is 11000401301. The next prime is 11000401333. The reversal of 11000401314 is 41310400011.

It is a junction number, because it is equal to n+sod(n) for n = 11000401293 and 11000401302.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1300852 + ... + 1309280.

It is an arithmetic number, because the mean of its divisors is an integer number (279656820).

Almost surely, 2^11000401314 is an apocalyptic number.

11000401314 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 11000401314, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13423527360).

11000401314 is an abundant number, since it is smaller than the sum of its proper divisors (15846653406).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11000401314 is a wasteful number, since it uses less digits than its factorization.

11000401314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8664 (or 8657 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 11000401314 its reverse (41310400011), we get a palindrome (52310801325).

The spelling of 11000401314 in words is "eleven billion, four hundred one thousand, three hundred fourteen".