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1100041113 = 3366680371
BaseRepresentation
bin100000110010001…
…0100101110011001
32211122220212201110
41001210110232121
54223102303423
6301053410533
736155123643
oct10144245631
92748825643
101100041113
11514a43196
12268499a49
13146b96602
14a614d893
1566893193
hex41914b99

1100041113 has 4 divisors (see below), whose sum is σ = 1466721488. Its totient is φ = 733360740.

The previous prime is 1100041069. The next prime is 1100041123. The reversal of 1100041113 is 3111400011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1100041113 - 216 = 1099975577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1100041123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183340183 + ... + 183340188.

It is an arithmetic number, because the mean of its divisors is an integer number (366680372).

Almost surely, 21100041113 is an apocalyptic number.

It is an amenable number.

1100041113 is a deficient number, since it is larger than the sum of its proper divisors (366680375).

1100041113 is an equidigital number, since it uses as much as digits as its factorization.

1100041113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 366680374.

The product of its (nonzero) digits is 12, while the sum is 12.

The square root of 1100041113 is about 33166.8676995582. The cubic root of 1100041113 is about 1032.2929759423.

Adding to 1100041113 its reverse (3111400011), we get a palindrome (4211441124).

The spelling of 1100041113 in words is "one billion, one hundred million, forty-one thousand, one hundred thirteen".

Divisors: 1 3 366680371 1100041113