11000421000313 has 4 divisors (see below), whose sum is σ = 11139666835840. Its totient is φ = 10861175164788.

The previous prime is 11000421000287. The next prime is 11000421000341. The reversal of 11000421000313 is 31300012400011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11000421000313 - 2¹⁷ = 11000420869241 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11000421000343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69622917645 + ... + 69622917802.

It is an arithmetic number, because the mean of its divisors is an integer number (2784916708960).

Almost surely, 2^{11000421000313} is an apocalyptic number.

It is an amenable number.

11000421000313 is a deficient number, since it is larger than the sum of its proper divisors (139245835527).

11000421000313 is an equidigital number, since it uses as much as digits as its factorization.

11000421000313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 139245835526.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 11000421000313 its reverse (31300012400011), we get a palindrome (42300433400324).

The spelling of 11000421000313 in words is "eleven trillion, four hundred twenty-one million, three hundred thirteen", and thus it is an aban number.