11000455035 has 16 divisors (see below), whose sum is σ = 17665681920. Its totient is φ = 5845258080.

The previous prime is 11000455031. The next prime is 11000455043. The reversal of 11000455035 is 53055400011.

It is not a de Polignac number, because 11000455035 - 2² = 11000455031 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11000454996 and 11000455014.

It is not an unprimeable number, because it can be changed into a prime (11000455031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1349005 + ... + 1357134.

It is an arithmetic number, because the mean of its divisors is an integer number (1104105120).

Almost surely, 2^11000455035 is an apocalyptic number.

11000455035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

11000455035 is a deficient number, since it is larger than the sum of its proper divisors (6665226885).

11000455035 is a wasteful number, since it uses less digits than its factorization.

11000455035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2706418.

The product of its (nonzero) digits is 1500, while the sum is 24.

Adding to 11000455035 its reverse (53055400011), we get a palindrome (64055855046).

The spelling of 11000455035 in words is "eleven billion, four hundred fifty-five thousand, thirty-five".