Base | Representation |
---|---|
bin | 11001000000110010000101… |
… | …011100001001000010010111 |
3 | 112102111100222111011021212021 |
4 | 121000302011130021002113 |
5 | 103404310104412210202 |
6 | 1025543323341234011 |
7 | 32112410663453152 |
oct | 3100620534110227 |
9 | 472440874137767 |
10 | 110004941131927 |
11 | 3206191949a7a6 |
12 | 10407840262907 |
13 | 494c562b8b36a |
14 | 1d243a627ac99 |
15 | cab7333dba37 |
hex | 640c85709097 |
110004941131927 has 2 divisors, whose sum is σ = 110004941131928. Its totient is φ = 110004941131926.
The previous prime is 110004941131919. The next prime is 110004941131931. The reversal of 110004941131927 is 729131149400011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110004941131927 - 23 = 110004941131919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110004941131027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55002470565963 + 55002470565964.
It is an arithmetic number, because the mean of its divisors is an integer number (55002470565964).
Almost surely, 2110004941131927 is an apocalyptic number.
110004941131927 is a deficient number, since it is larger than the sum of its proper divisors (1).
110004941131927 is an equidigital number, since it uses as much as digits as its factorization.
110004941131927 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 43.
The spelling of 110004941131927 in words is "one hundred ten trillion, four billion, nine hundred forty-one million, one hundred thirty-one thousand, nine hundred twenty-seven".
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