Base | Representation |
---|---|
bin | 10000000000100000011… |
… | …001001011111000100001 |
3 | 10220011102201202012001002 |
4 | 100000200121023320201 |
5 | 121010403101212321 |
6 | 2201205222321345 |
7 | 142322251035515 |
oct | 20004031137041 |
9 | 3804381665032 |
10 | 1100055100961 |
11 | 394592476183 |
12 | 159246289255 |
13 | 7c97232b3ab |
14 | 3b35892c145 |
15 | 1d93573720b |
hex | 1002064be21 |
1100055100961 has 2 divisors, whose sum is σ = 1100055100962. Its totient is φ = 1100055100960.
The previous prime is 1100055100957. The next prime is 1100055101023. The reversal of 1100055100961 is 1690015500011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 836712678400 + 263342422561 = 914720^2 + 513169^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100055100961 - 22 = 1100055100957 is a prime.
It is a super-3 number, since 3×11000551009613 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1100055100901) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550027550480 + 550027550481.
It is an arithmetic number, because the mean of its divisors is an integer number (550027550481).
Almost surely, 21100055100961 is an apocalyptic number.
It is an amenable number.
1100055100961 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100055100961 is an equidigital number, since it uses as much as digits as its factorization.
1100055100961 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1350, while the sum is 29.
The spelling of 1100055100961 in words is "one trillion, one hundred billion, fifty-five million, one hundred thousand, nine hundred sixty-one".
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