11000574229241 has 2 divisors, whose sum is σ = 11000574229242. Its totient is φ = 11000574229240.

The previous prime is 11000574229147. The next prime is 11000574229243. The reversal of 11000574229241 is 14292247500011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10637904096400 + 362670132841 = 3261580^2 + 602221^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000574229241 - 2²⁶ = 11000507120377 is a prime.

Together with 11000574229243, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11000574229195 and 11000574229204.

It is not a weakly prime, because it can be changed into another prime (11000574229243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500287114620 + 5500287114621.

It is an arithmetic number, because the mean of its divisors is an integer number (5500287114621).

Almost surely, 2^{11000574229241} is an apocalyptic number.

It is an amenable number.

11000574229241 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000574229241 is an equidigital number, since it uses as much as digits as its factorization.

11000574229241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 38.

The spelling of 11000574229241 in words is "eleven trillion, five hundred seventy-four million, two hundred twenty-nine thousand, two hundred forty-one".