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11000586893 is a prime number
BaseRepresentation
bin10100011111010111…
…11010001010001101
31001101122112201022012
422033223322022031
5140012122240033
65015324431005
7536414305622
oct121753721215
931348481265
1011000586893
1147355a982a
1221700a8465
1310640a181a
14764dc4349
15445b58248
hex28fafa28d

11000586893 has 2 divisors, whose sum is σ = 11000586894. Its totient is φ = 11000586892.

The previous prime is 11000586881. The next prime is 11000586911. The reversal of 11000586893 is 39868500011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8795063524 + 2205523369 = 93782^2 + 46963^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000586893 - 218 = 11000324749 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11000586893.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000586803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500293446 + 5500293447.

It is an arithmetic number, because the mean of its divisors is an integer number (5500293447).

Almost surely, 211000586893 is an apocalyptic number.

It is an amenable number.

11000586893 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000586893 is an equidigital number, since it uses as much as digits as its factorization.

11000586893 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 41.

The spelling of 11000586893 in words is "eleven billion, five hundred eighty-six thousand, eight hundred ninety-three".