Base | Representation |
---|---|
bin | 110011001110011011… |
… | …1110011001010000011 |
3 | 101111221111210122000220 |
4 | 1212130313303022003 |
5 | 3300243022234210 |
6 | 122311443314123 |
7 | 10643024021064 |
oct | 1463467631203 |
9 | 344844718026 |
10 | 110006055555 |
11 | 42720606800 |
12 | 193a097b943 |
13 | a4b183a286 |
14 | 5477d1c56b |
15 | 2cdc8e1c70 |
hex | 199cdf3283 |
110006055555 has 48 divisors (see below), whose sum is σ = 193656137472. Its totient is φ = 53283630400.
The previous prime is 110006055553. The next prime is 110006055557. The reversal of 110006055555 is 555550600011.
It is an interprime number because it is at equal distance from previous prime (110006055553) and next prime (110006055557).
It is not a de Polignac number, because 110006055555 - 21 = 110006055553 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is not an unprimeable number, because it can be changed into a prime (110006055553) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1841872 + ... + 1900658.
It is an arithmetic number, because the mean of its divisors is an integer number (4034502864).
Almost surely, 2110006055555 is an apocalyptic number.
110006055555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
110006055555 is a deficient number, since it is larger than the sum of its proper divisors (83650081917).
110006055555 is a wasteful number, since it uses less digits than its factorization.
110006055555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59848 (or 59837 counting only the distinct ones).
The product of its (nonzero) digits is 18750, while the sum is 33.
Adding to 110006055555 its reverse (555550600011), we get a palindrome (665556655566).
The spelling of 110006055555 in words is "one hundred ten billion, six million, fifty-five thousand, five hundred fifty-five".
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