Base | Representation |
---|---|
bin | 10000000000100000111… |
… | …000101000110111010110 |
3 | 10220011110022021002021212 |
4 | 100000200320220313112 |
5 | 121010412204034014 |
6 | 2201210115141422 |
7 | 142322411106104 |
oct | 20004070506726 |
9 | 3804408232255 |
10 | 1100063346134 |
11 | 394597097975 |
12 | 159248ba4872 |
13 | 7c973c572ac |
14 | 3b359a76c74 |
15 | 1d93631523e |
hex | 10020e28dd6 |
1100063346134 has 8 divisors (see below), whose sum is σ = 1650099471480. Its totient is φ = 550030188976.
The previous prime is 1100063346133. The next prime is 1100063346247. The reversal of 1100063346134 is 4316433600011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a self number, because there is not a number n which added to its sum of digits gives 1100063346134.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1100063346133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1051802 + ... + 1818354.
It is an arithmetic number, because the mean of its divisors is an integer number (206262433935).
Almost surely, 21100063346134 is an apocalyptic number.
1100063346134 is a deficient number, since it is larger than the sum of its proper divisors (550036125346).
1100063346134 is an equidigital number, since it uses as much as digits as its factorization.
1100063346134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1484094.
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 1100063346134 its reverse (4316433600011), we get a palindrome (5416496946145).
The spelling of 1100063346134 in words is "one trillion, one hundred billion, sixty-three million, three hundred forty-six thousand, one hundred thirty-four".
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