Base | Representation |
---|---|
bin | 10100011111011010… |
… | …01011010000111111 |
3 | 1001101200011121000021 |
4 | 22033231023100333 |
5 | 140012213402403 |
6 | 5015335513011 |
7 | 536420161306 |
oct | 121755132077 |
9 | 31350147007 |
10 | 11000919103 |
11 | 4735806389 |
12 | 2170228767 |
13 | 1064189ab5 |
14 | 76506d43d |
15 | 445bc18bd |
hex | 28fb4b43f |
11000919103 has 2 divisors, whose sum is σ = 11000919104. Its totient is φ = 11000919102.
The previous prime is 11000919071. The next prime is 11000919109. The reversal of 11000919103 is 30191900011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11000919103 - 25 = 11000919071 is a prime.
It is a super-2 number, since 2×110009191032 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000919109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500459551 + 5500459552.
It is an arithmetic number, because the mean of its divisors is an integer number (5500459552).
Almost surely, 211000919103 is an apocalyptic number.
11000919103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000919103 is an equidigital number, since it uses as much as digits as its factorization.
11000919103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 25.
The spelling of 11000919103 in words is "eleven billion, nine hundred nineteen thousand, one hundred three".
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