110009993323843 has 2 divisors, whose sum is σ = 110009993323844. Its totient is φ = 110009993323842.

The previous prime is 110009993323823. The next prime is 110009993323897. The reversal of 110009993323843 is 348323399900011.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (348323399900011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110009993323843 is a prime.

It is a super-2 number, since 2×110009993323843² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (110009993323823) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55004996661921 + 55004996661922.

It is an arithmetic number, because the mean of its divisors is an integer number (55004996661922).

Almost surely, 2^{110009993323843} is an apocalyptic number.

110009993323843 is a deficient number, since it is larger than the sum of its proper divisors (1).

110009993323843 is an equidigital number, since it uses as much as digits as its factorization.

110009993323843 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3779136, while the sum is 55.

The spelling of 110009993323843 in words is "one hundred ten trillion, nine billion, nine hundred ninety-three million, three hundred twenty-three thousand, eight hundred forty-three".