Base | Representation |
---|---|
bin | 1010000000010101111010… |
… | …1100100111001001101111 |
3 | 1102221200111121022211202201 |
4 | 2200011132230213021233 |
5 | 2420220021444414223 |
6 | 35221442321002331 |
7 | 2213540015055505 |
oct | 240053654471157 |
9 | 42850447284681 |
10 | 11000999998063 |
11 | 3561552781299 |
12 | 12980987833a7 |
13 | 61a50b66039a |
14 | 2a06462c2675 |
15 | 141264389ead |
hex | a015eb2726f |
11000999998063 has 2 divisors, whose sum is σ = 11000999998064. Its totient is φ = 11000999998062.
The previous prime is 11000999998013. The next prime is 11000999998069. The reversal of 11000999998063 is 36089999900011.
11000999998063 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11000999998063 - 217 = 11000999866991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11000999997986 and 11000999998004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000999998069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500499999031 + 5500499999032.
It is an arithmetic number, because the mean of its divisors is an integer number (5500499999032).
Almost surely, 211000999998063 is an apocalyptic number.
11000999998063 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000999998063 is an equidigital number, since it uses as much as digits as its factorization.
11000999998063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8503056, while the sum is 64.
The spelling of 11000999998063 in words is "eleven trillion, nine hundred ninety-nine million, nine hundred ninety-eight thousand, sixty-three".
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