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11001001010107 is a prime number
BaseRepresentation
bin1010000000010101111011…
…0000011110001110111011
31102221200111200020021000211
42200011132300132032323
52420220022224310412
635221442354411551
72213540026502203
oct240053660361673
942850450207024
1011001001010107
113561553302699
121298098b90bb7
1361a50b925c24
142a06464a7403
151412644d9ca7
hexa015ec1e3bb

11001001010107 has 2 divisors, whose sum is σ = 11001001010108. Its totient is φ = 11001001010106.

The previous prime is 11001001010071. The next prime is 11001001010123. The reversal of 11001001010107 is 70101010010011.

11001001010107 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (11001001010071) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (70101010010011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11001001010107 - 219 = 11001000485819 is a prime.

It is not a weakly prime, because it can be changed into another prime (11001001011107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500500505053 + 5500500505054.

It is an arithmetic number, because the mean of its divisors is an integer number (5500500505054).

Almost surely, 211001001010107 is an apocalyptic number.

11001001010107 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001001010107 is an equidigital number, since it uses as much as digits as its factorization.

11001001010107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7, while the sum is 13.

Adding to 11001001010107 its reverse (70101010010011), we get a palindrome (81102011020118).

The spelling of 11001001010107 in words is "eleven trillion, one billion, one million, ten thousand, one hundred seven".