11001009999983 has 2 divisors, whose sum is σ = 11001009999984. Its totient is φ = 11001009999982.

The previous prime is 11001009999953. The next prime is 11001010000021. The reversal of 11001009999983 is 38999990010011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11001009999983 - 2²² = 11001005805679 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001009999953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500504999991 + 5500504999992.

It is an arithmetic number, because the mean of its divisors is an integer number (5500504999992).

Almost surely, 2^{11001009999983} is an apocalyptic number.

11001009999983 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001009999983 is an equidigital number, since it uses as much as digits as its factorization.

11001009999983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1417176, while the sum is 59.

The spelling of 11001009999983 in words is "eleven trillion, one billion, nine million, nine hundred ninety-nine thousand, nine hundred eighty-three".