Base | Representation |
---|---|
bin | 10000000000100011001… |
… | …000010001101101110011 |
3 | 10220011112221010002202101 |
4 | 100000203020101231303 |
5 | 121011001324000201 |
6 | 2201213542201231 |
7 | 142323346133224 |
oct | 20004310215563 |
9 | 3804487102671 |
10 | 1100101000051 |
11 | 394606375909 |
12 | 159259723217 |
13 | 7c97b9ac011 |
14 | 3b360a7924b |
15 | 1d9397a1d01 |
hex | 10023211b73 |
1100101000051 has 2 divisors, whose sum is σ = 1100101000052. Its totient is φ = 1100101000050.
The previous prime is 1100100999953. The next prime is 1100101000081. The reversal of 1100101000051 is 1500001010011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100101000051 - 221 = 1100098902899 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100101000081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550050500025 + 550050500026.
It is an arithmetic number, because the mean of its divisors is an integer number (550050500026).
Almost surely, 21100101000051 is an apocalyptic number.
1100101000051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100101000051 is an equidigital number, since it uses as much as digits as its factorization.
1100101000051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5, while the sum is 10.
Adding to 1100101000051 its reverse (1500001010011), we get a palindrome (2600102010062).
The spelling of 1100101000051 in words is "one trillion, one hundred billion, one hundred one million, fifty-one", and thus it is an aban number.
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