1100101002121 has 4 divisors (see below), whose sum is σ = 1200110184144. Its totient is φ = 1000091820100.

The previous prime is 1100101002107. The next prime is 1100101002137. The reversal of 1100101002121 is 1212001010011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100101002121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1100101002098 and 1100101002107.

It is not an unprimeable number, because it can be changed into a prime (1100101000121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50004590995 + ... + 50004591016.

It is an arithmetic number, because the mean of its divisors is an integer number (300027546036).

Almost surely, 2^{1100101002121} is an apocalyptic number.

1100101002121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1100101002121 is a deficient number, since it is larger than the sum of its proper divisors (100009182023).

1100101002121 is a wasteful number, since it uses less digits than its factorization.

1100101002121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100009182022.

The product of its (nonzero) digits is 4, while the sum is 10.

Adding to 1100101002121 its reverse (1212001010011), we get a palindrome (2312102012132).

The spelling of 1100101002121 in words is "one trillion, one hundred billion, one hundred one million, two thousand, one hundred twenty-one".