Base | Representation |
---|---|
bin | 10100011111011011… |
… | …00001111100011001 |
3 | 1001101200100022102122 |
4 | 22033231201330121 |
5 | 140012224340433 |
6 | 5015341511025 |
7 | 536421026156 |
oct | 121755417431 |
9 | 31350308378 |
10 | 11001011993 |
11 | 473586a154 |
12 | 2170272475 |
13 | 10641c016a |
14 | 76509522d |
15 | 445bde198 |
hex | 28fb61f19 |
11001011993 has 2 divisors, whose sum is σ = 11001011994. Its totient is φ = 11001011992.
The previous prime is 11001011977. The next prime is 11001012031. The reversal of 11001011993 is 39911010011.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6513619849 + 4487392144 = 80707^2 + 66988^2 .
It is an emirp because it is prime and its reverse (39911010011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11001011993 - 24 = 11001011977 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (11001091993) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500505996 + 5500505997.
It is an arithmetic number, because the mean of its divisors is an integer number (5500505997).
Almost surely, 211001011993 is an apocalyptic number.
It is an amenable number.
11001011993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001011993 is an equidigital number, since it uses as much as digits as its factorization.
11001011993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 243, while the sum is 26.
The spelling of 11001011993 in words is "eleven billion, one million, eleven thousand, nine hundred ninety-three".
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