Base | Representation |
---|---|
bin | 1010000000010101111101… |
… | …1011001101010111011001 |
3 | 1102221200112110022102210112 |
4 | 2200011133123031113121 |
5 | 2420220033111310314 |
6 | 35221443434454105 |
7 | 2213540223642254 |
oct | 240053733152731 |
9 | 42850473272715 |
10 | 11001012213209 |
11 | 3561559664757 |
12 | 12980a0894335 |
13 | 61a511049295 |
14 | 2a0647b8209b |
15 | 14126549e43e |
hex | a015f6cd5d9 |
11001012213209 has 2 divisors, whose sum is σ = 11001012213210. Its totient is φ = 11001012213208.
The previous prime is 11001012213157. The next prime is 11001012213287. The reversal of 11001012213209 is 90231221010011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10820448408025 + 180563805184 = 3289445^2 + 424928^2 .
It is a cyclic number.
It is not a de Polignac number, because 11001012213209 - 216 = 11001012147673 is a prime.
It is not a weakly prime, because it can be changed into another prime (11001012213299) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500506106604 + 5500506106605.
It is an arithmetic number, because the mean of its divisors is an integer number (5500506106605).
Almost surely, 211001012213209 is an apocalyptic number.
It is an amenable number.
11001012213209 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001012213209 is an equidigital number, since it uses as much as digits as its factorization.
11001012213209 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 23.
The spelling of 11001012213209 in words is "eleven trillion, one billion, twelve million, two hundred thirteen thousand, two hundred nine".
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