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11001020021103 = 37523858096243
BaseRepresentation
bin1010000000010101111111…
…1000111111100101101111
31102221200120000000010012210
42200011133320333211233
52420220042111133403
635221444314101503
72213540350211640
oct240053770774557
942850500003183
1011001020021103
113561563007962
1212980a341a893
1361a512851138
142a0648c156c7
15141265ee2b03
hexa015fe3f96f

11001020021103 has 8 divisors (see below), whose sum is σ = 16763459079808. Its totient is φ = 6286297154904.

The previous prime is 11001020021093. The next prime is 11001020021149. The reversal of 11001020021103 is 30112002010011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11001020021103 - 29 = 11001020020591 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11001020026103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 261929048101 + ... + 261929048142.

It is an arithmetic number, because the mean of its divisors is an integer number (2095432384976).

Almost surely, 211001020021103 is an apocalyptic number.

11001020021103 is a deficient number, since it is larger than the sum of its proper divisors (5762439058705).

11001020021103 is an equidigital number, since it uses as much as digits as its factorization.

11001020021103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 523858096253.

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 11001020021103 its reverse (30112002010011), we get a palindrome (41113022031114).

The spelling of 11001020021103 in words is "eleven trillion, one billion, twenty million, twenty-one thousand, one hundred three".

Divisors: 1 3 7 21 523858096243 1571574288729 3667006673701 11001020021103