11001099953 has 2 divisors, whose sum is σ = 11001099954. Its totient is φ = 11001099952.

The previous prime is 11001099947. The next prime is 11001100013. The reversal of 11001099953 is 35999010011.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10525118464 + 475981489 = 102592^2 + 21817^2 .

It is an emirp because it is prime and its reverse (35999010011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11001099953 - 2²² = 10996905649 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (11001099913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500549976 + 5500549977.

It is an arithmetic number, because the mean of its divisors is an integer number (5500549977).

Almost surely, 2^11001099953 is an apocalyptic number.

It is an amenable number.

11001099953 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001099953 is an equidigital number, since it uses as much as digits as its factorization.

11001099953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10935, while the sum is 38.

The spelling of 11001099953 in words is "eleven billion, one million, ninety-nine thousand, nine hundred fifty-three".