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110010999997 is a prime number
BaseRepresentation
bin110011001110100101…
…0101010010010111101
3101111221212002211112101
41212131022222102331
53300300303444442
6122312141305101
710643114033263
oct1463512522275
9344855084471
10110010999997
1142723383618
12193a2565191
13a4b287b992
145478848433
152cdd06bcb7
hex199d2aa4bd

110010999997 has 2 divisors, whose sum is σ = 110010999998. Its totient is φ = 110010999996.

The previous prime is 110010999979. The next prime is 110011000003. The reversal of 110010999997 is 799999010011.

Together with previous prime (110010999979) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 62169936921 + 47841063076 = 249339^2 + 218726^2 .

It is a cyclic number.

It is not a de Polignac number, because 110010999997 - 235 = 75651261629 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110010999697) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005499998 + 55005499999.

It is an arithmetic number, because the mean of its divisors is an integer number (55005499999).

Almost surely, 2110010999997 is an apocalyptic number.

It is an amenable number.

110010999997 is a deficient number, since it is larger than the sum of its proper divisors (1).

110010999997 is an equidigital number, since it uses as much as digits as its factorization.

110010999997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 413343, while the sum is 55.

The spelling of 110010999997 in words is "one hundred ten billion, ten million, nine hundred ninety-nine thousand, nine hundred ninety-seven".