110011009981 has 2 divisors, whose sum is σ = 110011009982. Its totient is φ = 110011009980.

The previous prime is 110011009957. The next prime is 110011010003. The reversal of 110011009981 is 189900110011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95141402500 + 14869607481 = 308450^2 + 121941^2 .

It is a cyclic number.

It is not a de Polignac number, because 110011009981 - 2¹⁵ = 110010977213 is a prime.

It is a super-3 number, since 3×110011009981³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110011009921) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005504990 + 55005504991.

It is an arithmetic number, because the mean of its divisors is an integer number (55005504991).

Almost surely, 2^110011009981 is an apocalyptic number.

It is an amenable number.

110011009981 is a deficient number, since it is larger than the sum of its proper divisors (1).

110011009981 is an equidigital number, since it uses as much as digits as its factorization.

110011009981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 31.

Adding to 110011009981 its reverse (189900110011), we get a palindrome (299911119992).

The spelling of 110011009981 in words is "one hundred ten billion, eleven million, nine thousand, nine hundred eighty-one".