Base | Representation |
---|---|
bin | 1010000000010110010010… |
… | …1101111001110101010111 |
3 | 1102221200202122101021102001 |
4 | 2200011210231321311113 |
5 | 2420220223324000043 |
6 | 35221500325500131 |
7 | 2213542352423041 |
oct | 240054455716527 |
9 | 42850678337361 |
10 | 11001101000023 |
11 | 35615a4797592 |
12 | 1298106571647 |
13 | 61a526564c64 |
14 | 2a0655894a91 |
15 | 14126d18b74d |
hex | a0164b79d57 |
11001101000023 has 2 divisors, whose sum is σ = 11001101000024. Its totient is φ = 11001101000022.
The previous prime is 11001100999969. The next prime is 11001101000119. The reversal of 11001101000023 is 32000010110011.
11001101000023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11001101000023 - 217 = 11001100868951 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11001100999973 and 11001101000009.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001101009023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500550500011 + 5500550500012.
It is an arithmetic number, because the mean of its divisors is an integer number (5500550500012).
Almost surely, 211001101000023 is an apocalyptic number.
11001101000023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001101000023 is an equidigital number, since it uses as much as digits as its factorization.
11001101000023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 10.
Adding to 11001101000023 its reverse (32000010110011), we get a palindrome (43001111110034).
The spelling of 11001101000023 in words is "eleven trillion, one billion, one hundred one million, twenty-three", and thus it is an aban number.
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