1100110111153 has 2 divisors, whose sum is σ = 1100110111154. Its totient is φ = 1100110111152.

The previous prime is 1100110111103. The next prime is 1100110111169. The reversal of 1100110111153 is 3511110110011.

It is an a-pointer prime, because the next prime (1100110111169) can be obtained adding 1100110111153 to its sum of digits (16).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1010201887744 + 89908223409 = 1005088^2 + 299847^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100110111153 - 2²¹ = 1100108014001 is a prime.

It is a super-3 number, since 3×1100110111153³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1100110111103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550055055576 + 550055055577.

It is an arithmetic number, because the mean of its divisors is an integer number (550055055577).

Almost surely, 2^{1100110111153} is an apocalyptic number.

It is an amenable number.

1100110111153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100110111153 is an equidigital number, since it uses as much as digits as its factorization.

1100110111153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 16.

Adding to 1100110111153 its reverse (3511110110011), we get a palindrome (4611220221164).

The spelling of 1100110111153 in words is "one trillion, one hundred billion, one hundred ten million, one hundred eleven thousand, one hundred fifty-three".