11001101220223 has 16 divisors (see below), whose sum is σ = 11684916688896. Its totient is φ = 10344235033440.

The previous prime is 11001101220217. The next prime is 11001101220229. The reversal of 11001101220223 is 32202210110011.

It is an interprime number because it is at equal distance from previous prime (11001101220217) and next prime (11001101220229).

It is a cyclic number.

It is not a de Polignac number, because 11001101220223 - 2⁵ = 11001101220191 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11001101220197 and 11001101220206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11001101220229) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44494711 + ... + 44741272.

It is an arithmetic number, because the mean of its divisors is an integer number (730307293056).

Almost surely, 2^{11001101220223} is an apocalyptic number.

11001101220223 is a deficient number, since it is larger than the sum of its proper divisors (683815468673).

11001101220223 is an equidigital number, since it uses as much as digits as its factorization.

11001101220223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 89236134.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 11001101220223 its reverse (32202210110011), we get a palindrome (43203311330234).

The spelling of 11001101220223 in words is "eleven trillion, one billion, one hundred one million, two hundred twenty thousand, two hundred twenty-three".