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11001101220197 = 111000100110927
BaseRepresentation
bin1010000000010110010010…
…1110101111100101100101
31102221200202122210110102122
42200011210232233211211
52420220223403021242
635221500334315325
72213542354330664
oct240054456574545
942850678713378
1011001101220197
1135615a4927a50
121298106658b45
1361a52661123a
142a0655910ddb
1514126d1d1ad2
hexa0164baf965

11001101220197 has 4 divisors (see below), whose sum is σ = 12001201331136. Its totient is φ = 10001001109260.

The previous prime is 11001101220191. The next prime is 11001101220209. The reversal of 11001101220197 is 79102210110011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11001101220197 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11001101220191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500050055453 + ... + 500050055474.

It is an arithmetic number, because the mean of its divisors is an integer number (3000300332784).

Almost surely, 211001101220197 is an apocalyptic number.

It is an amenable number.

11001101220197 is a deficient number, since it is larger than the sum of its proper divisors (1000100110939).

11001101220197 is a wasteful number, since it uses less digits than its factorization.

11001101220197 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1000100110938.

The product of its (nonzero) digits is 252, while the sum is 26.

The spelling of 11001101220197 in words is "eleven trillion, one billion, one hundred one million, two hundred twenty thousand, one hundred ninety-seven".

Divisors: 1 11 1000100110927 11001101220197